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.\" ========================================================================
.\"
.IX Title "SCRYPT 7"
.TH SCRYPT 7 "2023-09-11" "1.1.1w" "OpenSSL"
.\" For nroff, turn off justification. Always turn off hyphenation; it makes
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.SH "NAME"
scrypt \- EVP_PKEY scrypt KDF support
.SH "DESCRIPTION"
.IX Header "DESCRIPTION"
The \s-1EVP_PKEY_SCRYPT\s0 algorithm implements the scrypt password based key
derivation function, as described in \s-1RFC 7914. \s0 It is memory-hard in the sense
that it deliberately requires a significant amount of \s-1RAM\s0 for efficient
computation. The intention of this is to render brute forcing of passwords on
systems that lack large amounts of main memory (such as GPUs or ASICs)
computationally infeasible.
.PP
scrypt provides three work factors that can be customized: N, r and p. N, which
has to be a positive power of two, is the general work factor and scales \s-1CPU\s0
time in an approximately linear fashion. r is the block size of the internally
used hash function and p is the parallelization factor. Both r and p need to be
greater than zero. The amount of \s-1RAM\s0 that scrypt requires for its computation
is roughly (128 * N * r * p) bytes.
.PP
In the original paper of Colin Percival (\*(L"Stronger Key Derivation via
Sequential Memory-Hard Functions\*(R", 2009), the suggested values that give a
computation time of less than 5 seconds on a 2.5 GHz Intel Core 2 Duo are N =
2^20 = 1048576, r = 8, p = 1. Consequently, the required amount of memory for
this computation is roughly 1 GiB. On a more recent \s-1CPU \s0(Intel i7\-5930K at 3.5
GHz), this computation takes about 3 seconds. When N, r or p are not specified,
they default to 1048576, 8, and 1, respectively. The default amount of \s-1RAM\s0 that
may be used by scrypt defaults to 1025 MiB.
.SH "NOTES"
.IX Header "NOTES"
A context for scrypt can be obtained by calling:
.PP
.Vb 1
\& EVP_PKEY_CTX *pctx = EVP_PKEY_CTX_new_id(EVP_PKEY_SCRYPT, NULL);
.Ve
.PP
The output length of an scrypt key derivation is specified via the
length parameter to the \fIEVP_PKEY_derive\fR\|(3) function.
.SH "EXAMPLES"
.IX Header "EXAMPLES"
This example derives a 64\-byte long test vector using scrypt using the password
\&\*(L"password\*(R", salt \*(L"NaCl\*(R" and N = 1024, r = 8, p = 16.
.PP
.Vb 2
\& EVP_PKEY_CTX *pctx;
\& unsigned char out[64];
\&
\& size_t outlen = sizeof(out);
\& pctx = EVP_PKEY_CTX_new_id(EVP_PKEY_SCRYPT, NULL);
\&
\& if (EVP_PKEY_derive_init(pctx) <= 0) {
\& error("EVP_PKEY_derive_init");
\& }
\& if (EVP_PKEY_CTX_set1_pbe_pass(pctx, "password", 8) <= 0) {
\& error("EVP_PKEY_CTX_set1_pbe_pass");
\& }
\& if (EVP_PKEY_CTX_set1_scrypt_salt(pctx, "NaCl", 4) <= 0) {
\& error("EVP_PKEY_CTX_set1_scrypt_salt");
\& }
\& if (EVP_PKEY_CTX_set_scrypt_N(pctx, 1024) <= 0) {
\& error("EVP_PKEY_CTX_set_scrypt_N");
\& }
\& if (EVP_PKEY_CTX_set_scrypt_r(pctx, 8) <= 0) {
\& error("EVP_PKEY_CTX_set_scrypt_r");
\& }
\& if (EVP_PKEY_CTX_set_scrypt_p(pctx, 16) <= 0) {
\& error("EVP_PKEY_CTX_set_scrypt_p");
\& }
\& if (EVP_PKEY_derive(pctx, out, &outlen) <= 0) {
\& error("EVP_PKEY_derive");
\& }
\&
\& {
\& const unsigned char expected[sizeof(out)] = {
\& 0xfd, 0xba, 0xbe, 0x1c, 0x9d, 0x34, 0x72, 0x00,
\& 0x78, 0x56, 0xe7, 0x19, 0x0d, 0x01, 0xe9, 0xfe,
\& 0x7c, 0x6a, 0xd7, 0xcb, 0xc8, 0x23, 0x78, 0x30,
\& 0xe7, 0x73, 0x76, 0x63, 0x4b, 0x37, 0x31, 0x62,
\& 0x2e, 0xaf, 0x30, 0xd9, 0x2e, 0x22, 0xa3, 0x88,
\& 0x6f, 0xf1, 0x09, 0x27, 0x9d, 0x98, 0x30, 0xda,
\& 0xc7, 0x27, 0xaf, 0xb9, 0x4a, 0x83, 0xee, 0x6d,
\& 0x83, 0x60, 0xcb, 0xdf, 0xa2, 0xcc, 0x06, 0x40
\& };
\&
\& assert(!memcmp(out, expected, sizeof(out)));
\& }
\&
\& EVP_PKEY_CTX_free(pctx);
.Ve
.SH "CONFORMING TO"
.IX Header "CONFORMING TO"
\&\s-1RFC 7914\s0
.SH "SEE ALSO"
.IX Header "SEE ALSO"
\&\fIEVP_PKEY_CTX_set1_scrypt_salt\fR\|(3),
\&\fIEVP_PKEY_CTX_set_scrypt_N\fR\|(3),
\&\fIEVP_PKEY_CTX_set_scrypt_r\fR\|(3),
\&\fIEVP_PKEY_CTX_set_scrypt_p\fR\|(3),
\&\fIEVP_PKEY_CTX_set_scrypt_maxmem_bytes\fR\|(3),
\&\fIEVP_PKEY_CTX_new\fR\|(3),
\&\fIEVP_PKEY_CTX_ctrl_str\fR\|(3),
\&\fIEVP_PKEY_derive\fR\|(3)
.SH "COPYRIGHT"
.IX Header "COPYRIGHT"
Copyright 2017\-2019 The OpenSSL Project Authors. All Rights Reserved.
.PP
Licensed under the OpenSSL license (the \*(L"License\*(R"). You may not use
this file except in compliance with the License. You can obtain a copy
in the file \s-1LICENSE\s0 in the source distribution or at
<https://www.openssl.org/source/license.html>.